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Neon gas is generally used in the sign boards. If it emits strongly at `616 nm`, calculate a. The frequency of emission, b. The distance travelled by this radiation in `30 s` c. The energy of quantum and d. The number of quanta present if it produces `2 J` of energy. |
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Answer» `lambda=616 nm=616xx10^(-9)m` a. Frequency, `v=c/lambda=(3.0xx10^(8)m s^(-1))/(616xx10^(-9) m)=4.87xx10^(14) s^(-1)` b. Velocity of radiation `=3.0xx10^(8) m s^(-1)` `:.` Distance travelled in `30 s=30xx3xx10^(8) m` c. `E=hv=h c/lambda` `((6.626xx10^(-34)Js)(3.0xx10^(8) m s^(-1)))/(616xx10^(-9) m)` `=32.27xx10^(-20)J` d. Number of quanta in `2J` of energy`=2/(32.27xx10^(-28))` `=6.2xx10^(18)` |
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