nd(c) 100d) 20OngA beggar have some coins of 10 paise, 20 paiseand 01

1.	nd(c) 100d) 20OngA beggar have some coins of 10 paise, 20 paiseand 01 Rs in the end of the day in the ratio of10 17:7 of 10 paise, 20 paise and 01 Rs. Ifhe had Rs. 57 in the end of the day Then whatis the number of coin of 20 paise?(a) 55(c) 80421 35(b) 60(d) 85s 1s
Answer» Let no. of 10 paise coins are 10xNo. of 20 paise coins are 17xNo. of 1 Rs coins are 7x As per given condition.110x +.217x + 17x = 57x + 3.4x + 7x = 5711.4 x = 57x = 570/114 = 10/2x = 5 Number of 20 paise coins = 175 = 85

nd(c) 100d) 20OngA beggar have some coins of 10 paise, 20 paiseand 01 Rs in the end of the day in the ratio of10 17:7 of 10 paise, 20 paise and 01 Rs. Ifhe had Rs. 57 in the end of the day Then whatis the number of coin of 20 paise?(a) 55(c) 80421 35(b) 60(d) 85s 1s

Answer»

Let no. of 10 paise coins are 10xNo. of 20 paise coins are 17xNo. of 1 Rs coins are 7x

As per given condition.1*10x +.2*17x + 1*7x = 57x + 3.4x + 7x = 5711.4 x = 57x = 570/114 = 10/2x = 5

Number of 20 paise coins = 17*5 = 85