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NCERT10 CLASS MATHS EX6.2 QUESTION5​

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Answer:

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Step-by-step explanation:

5. In figure, DE  OQ and DF  OR. Show that EF  QR.

In PQO, DE  OQ  

[Basic Proportionality theorem] ……….(i)

And in POR, DF  OR

[Basic Proportionality theorem] ……….(II)  

From eq. (i) and (ii), we have

EF|| QR [By the CONVERSE of BPT]



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