Ncert 11 class chapter 1 question number 1.35 chemistry

1.	Ncert 11 class chapter 1 question number 1.35 chemistry
Answer» @HEY dear!! Number of MOLES of HCL USED:- $= \frac{mv}{1000}$ $= \frac{0.75 \times 25}{1000}$ $= 0.01875$ Number of moles of CaCo3 to react with HCL:-- $= \frac{1}{2 } \times no \: of \: moles \: of \: hcl$ $= \frac{1}{2} \times 0.01875$ $= 9.37 5\times {10}^{ - 3}$ Mass of CaCo3 = no. of moles × molar mass $= 9.375 \times {10}^{ - 3 } \times 100$ $= 0.9375 \: g$ Thanks!! hope it MAY help you✔✔

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