1.

Name some hydrocarbonds whose carbons and hydrogen are distinguishing to solve empirical formula and molecular formula question. Like benzene, Ethene.....

Answer» MoleculeStep 1 
CNH2N +2
Step 2 
Adjust
Step 3 
Subtract
Step 4 
Divide
HDI
Benzene 
C6H6
14614 - 6 = 88/2 = 44
Pyridine 
C5H5N
125–1 = 412 - 4 = 88/2 = 44
Ethylamine 
C2H7N
67–1 = 66 – 6 = 0 0
2-Butanol 
C4H9OH
101010-10 = 0 0
Chlorobenzoic ACID C7H5O2Cl165+1=616-6 = 1010/2=55


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