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Name some hydrocarbonds whose carbons and hydrogen are distinguishing to solve empirical formula and molecular formula question. Like benzene, Ethene..... |
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Answer» MoleculeStep 1 CNH2N +2Step 2 AdjustStep 3 SubtractStep 4 DivideHDIBenzene C6H614614 - 6 = 88/2 = 44Pyridine C5H5N125–1 = 412 - 4 = 88/2 = 44Ethylamine C2H7N67–1 = 66 – 6 = 0 02-Butanol C4H9OH101010-10 = 0 0Chlorobenzoic ACID C7H5O2Cl165+1=616-6 = 1010/2=55 |
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