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Name of fourth and fifth member of homologous series of acetic acid |
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Answer» So, if we put n = 4 in the general FORMULA CnH2n +1OH then the molecular formula of the fourth MEMBER of the homologous SERIES will BECOME C4H2 * 4 + 1OH or C4H9OH. So, if we put n = 5 in the general formula CnH2n + 1OH, then the molecular formula of the fifth member of the alcohol series will become C5H2 * 5 + 1OH or C5H11OH.So, if we put n = 5 in the general formula CnH2n + 1OH, then the molecular formula of the fifth member of the alcohol series will become C5H2 * 5 + 1OH or C5H11OH. |
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