1.

Na2S2O3.5H2O equivalent mass in Na2S2O3 in the reaction is 2Na2S2O3+ I2gives Na2S4O6 + 2Na reactuonI

Answer»

The equivalent weight of oxidising or reducing agent is = molecular weight / NUMBER of electron PER MOLE transfer during the REACTION.
In above MENTIONED reaction there is transfer of 2 electrons per 2 moles of Na2S2O3 as follows :
2S2O32- → S4O62- + 2e-
So the equivalent weight of Na2S2O3 is same as molecular weight = 158.11 g mol-1



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