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N2 with pressure 10 atm and H2 with pressure 30 atm, both with volume 10 liter at 27^oC are passed into a reactor, how many moles NH3 is produced?(a) 4(b) 8(c) 12(d) 16 |
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Answer» Correct choice is (b) 8 For explanation: The reaction is N2 + 3H2 -> 2NH3, moles of N2 = 10*10/(0.0821*300) = 4, moles of H2 = 30*10/(0.0821*300) = 12, => extent of reaction = (0 – 4)/(-1) = 4, => moles of NH3 = 4*2 = 8. |
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