1.

न रू ।सब्ध काजए केsin(A+B)= tanA+tan BcosA cosB

Answer»

sin(a+B) / cosacosB = tana + tanB

sin(a+B) = sinacosB + cosasinB (identity)

sin(a+B) / cosacosB = (sinacosB + cosasinB) / (cosacosB)

= sinacosB/cosacosB + cosasinB/cosacosB

= sina/cosa + sinB/cosB

= tana + tanB



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