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न रू ।सब्ध काजए केsin(A+B)= tanA+tan BcosA cosB |
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Answer» sin(a+B) / cosacosB = tana + tanB sin(a+B) = sinacosB + cosasinB (identity) sin(a+B) / cosacosB = (sinacosB + cosasinB) / (cosacosB) = sinacosB/cosacosB + cosasinB/cosacosB = sina/cosa + sinB/cosB = tana + tanB |
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