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^{n} P_{4} :^{n+1} P_{4}=3 : 4 |
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Answer» nPr = n!/(n-r)!HencenP4 : n+1P4 = n!/(n-4)! : (n+1)!/(n-3)! = n!/(n-4)! : (n+1)(n)!/(n-3)(n-4)!Hencen-3/n+1 = 3/44n - 12 = 3n+3 n = 15 |
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