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N,n+4 n+12and n+16 is devisle by 5 where is any positive integer solution |
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Answer» Hey there !! Any positive integer is of the form 5q , 5q + 1 , 5q + 2 here , b = 5 r = 0 , 1 , 2 , 3 , 4 when r = 0 , n = 5q n = 5q ----> DIVISIBLE by 5 ===> [1] n + 4 = 5q + 4 [ not divisible by 5 ] n + 6 = 5q + 6 [ not divisible by 5 ] n + 12 = 5q + 12 [ not divisible by 5 ] ------------------------------------------- when r = 1 , n = 5q + 1 n = 5q + 1 [ not divisible by 5 ] n + 4 = 5q + 5 = 5 [Q+ 1] ----> divisible by 5 ===> [2] n + 6 = 5q + 7 [ not divisible by 5 ] n + 12 = 5q + 13 [ not divisible by 5 ] ---------------------------------------- when r = 3 , n = 5q + 3 n = 5q + 3 [ not divisible by 5 ] n + 4 = 5q + 7 [ not divisible by 5 ] n + 8 = 5q + 11 [ not divisible by 5 ] n + 6 = 5q + 9 [ not divisible by 5 ] n + 12 = 5q + 15 = 5 [ q + 3 ] ---> divisible by 5 ====> [3] ---------------------------------------------------- when r = 4 , n = 5q + 4 n = 5q + 4 [ not divisible by 5 ] n + 4 = 5q + 8 [ not divisible by 5 ] n + 6 = 5q + 10 = 5 [ q + 2 ] ---> divisible by 5 ====> [4] n + 12 = 5q + 16 [ not divisible by 5 ] from 1 , 2 , 3 , 4 its clear that one and only one out of n, n+4, , n+12 and n+6 is divisible by 5 |
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