`n` identical resistors are taken `(n)/(2)` resistors are connected in series and the remaining are connected in paralle. The series connected group is kept in the left gap of a meter bridge and the parallel connected group in the right gap. The distance of te balance point from the left end of the wire isA. `(100n^(2))/(n^(2)+4)`B. `(100n^(2))/(n^(2)+1)`C. `(400)/(n^(2)+4)`D. `(400)/(n^(2)+1)`

`n` identical resistors are taken `(n)/(2)` resistors are connected in

1.	`n` identical resistors are taken `(n)/(2)` resistors are connected in series and the remaining are connected in paralle. The series connected group is kept in the left gap of a meter bridge and the parallel connected group in the right gap. The distance of te balance point from the left end of the wire isA. `(100n^(2))/(n^(2)+4)`B. `(100n^(2))/(n^(2)+1)`C. `(400)/(n^(2)+4)`D. `(400)/(n^(2)+1)`
Answer» Correct Answer - A `(X)/(100-X)=((nr)/(2))/((2r)/(n))`

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