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`N` identical cells, each emf `E` and internal resistance `r` are joined in series. Out of `N` cells, `n` cells are wrongly connected i.e., their terminals are connected in reverse of the required for series connection `(n lt (N)/(2))`. Let `E_(0)` be the emf of resulting battery and `r_(0)` be its internal resistance. ThenA. `E_(0) = (N - n) E, r_(0) = (N - n) r`B. `E_(0) = (N - 2n) E, r_(0) = (N - 2n) r`C. `E_(0) = (N - 2n) E, r_(0) = N r`D. `E_(0) = (N - n) E, r_(0) = N r` |
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Answer» Correct Answer - C (c ) For every cell that is wrongly connected, the emf decreases by `2 E`. However, internal resistance does not depend on the direction and therefore remains same for all cells. |
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