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न 860 0 00560 6- 2 आए 9 008 9. |
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Answer» LHS = Tan^3A / ( 1+ Tan^2A) + Cot^3A / (1 + Cot^2a) = Tan^3A / Sec^2A + Cot^3A / Cosec^2A = (sin^3A/cos^3A) / (1 / Cos^2A) + (Cos^3A/Sin^3A) / (1 / Sin^2A) = Sin^3A/CosA + Cos^3A/SinA = (Sin^4A + Cos^4A) / SinA.CosA = [ (Sin^2A + Cos^2A)^2 - 2Sin^2A.Cos^2A] / SinA.CosA = ( 1- 2Sin^A.Cos^A)/ SinA.CosA RHS = SecA CosecA - 2sinAcosA = 1/CosA . 1/SinA - 2SinACosA = (1 - Sin^2A.Cos^2A) / sinAcosA Hence LHS = RHS (PROVED) hit like if you find it useful |
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