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Mutually perpendicular tangents `T Aa n dT B`are drawn to `y^2=4a x`. Then find the minimum length of `A Bdot`A. aB. 2aC. 4aD. 8a

Answer» Correct Answer - C
We know that tangents at the ends of focal chord are perpendicualar. Thus, the chord of contanct of perpendicualar tangents is a focal chord. Also, latusrectum is a focal chord of minimum length. Hence, the minimum length of AB is 4a.


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