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Multiply the following:(3/4×4/3y)(2/3×-3/2y)\((\frac34\times\frac{4}{3y})(\frac23\times\frac{-3}{2y})\) |
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Answer» \((\frac34\times\frac{4}{3y})(\frac23\times\frac{-3}{2y})\) = \(\frac1y\times-\frac1y=-\frac1{y^2}\) |
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