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Multiply (2y+3)×(4y-2) give answer in step by step |
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Answer» ONG>Answer: (2y+3) × (4y-2) = 8y²-4y +12y -6 =8y²+8y-6 If you want to find out the ROOTS it will be : 8y²+8y-6
Here, a=8 , b=8 , c=-6 =-b±√b²-4ac/2a =-8±√(8) ²-4(8) (-6) /2*8
=-8±√64+192/16 =-8±√256/16 =-8±√(16)²/16 =-8±16/16 so, y=-8+16/16 or y=-8-16/16
=8/16=1/2 y= -24/16 =-3/2 so , the required roots are (1/2) and( -3/2) |
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