Mrs. Kaushik has a square plot with side 30 metres. She wants to const

1.	Mrs. Kaushik has a square plot with side 30 metres. She wants to construct a houseof length 25 m and width 20 m in the middle of the plot. A garden is developed aroundthe house. Find the area of garden.
Answer» Answer: SIDE of square plot = 25 so area of square plot = 25×25=625square metere length and BREADTH of house is 20 and 15 m respectively so area of house = 20×15=300square meter *area* of *GARDEN=area* of *square* *plot* - *area* of *house* 625-300=325 since cost of devoloping garden=₹55 TOAL cost of devoloping garden area of 325sqm=325×55=17,875

Mrs. Kaushik has a square plot with side 30 metres. She wants to construct a houseof length 25 m and width 20 m in the middle of the plot. A garden is developed aroundthe house. Find the area of garden.

Answer»

Answer:

SIDE of square plot = 25

so area of square plot = 25×25=625square metere

length and BREADTH of house is 20 and 15 m respectively

so area of house = 20×15=300square meter

area of GARDEN=area of square plot - area of house

625-300=325

since cost of devoloping garden=₹55

TOAL cost of devoloping garden area of 325sqm=325×55=17,875

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Mrs. Kaushik has a square plot with side 30 metres. She wants to construct a houseof length 25 m and width 20 m in the middle of the plot. A garden is developed aroundthe house. Find the area of garden.​

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Mrs. Kaushik has a square plot with side 30 metres. She wants to construct a houseof length 25 m and width 20 m in the middle of the plot. A garden is developed aroundthe house. Find the area of garden.