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Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.Find their present ages?​

Answer»

ong>Given : MRS. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.

To Find : Their present ages.

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❍Let the present AGE of Nilu be "x" years.

Therefore,the present age of Nilu's mother = (x + 27) years.

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{\underline{\boldsymbol{\pink{According \ to \ the \ question \ :}}}}

So,after 8 years,

Nilu's age = (x + 8),and Mrs Jain's age = (x + 27 + 8) = (x + 35)years.

:\implies{ \sf{\pink{x + 35 = 2(x + 8)}}}

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Expanding the brackets,We get

:\implies{ \sf{\pink{x + 35 = 2x + 16}}}

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Transporing x to RHS and 16 to LHS,We get

:\implies{ \sf{\pink{35-16=2x-x}}}

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:\implies{ \sf{\pink{x=19}}}

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So,The present age of Nilu = x = 19 years.And the present age of Nilu's mother that is Mrs Jain = x + 27 = 19 + 27 = 46 years.



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