Motber is 25 year older than her son. Find son's age if after 8 years

1.	Motber is 25 year older than her son. Find son's age if after 8 years ratio of son'sage to mother's age will be4
Answer» Let present age of son be X years. Age of mother = ( X + 25 ) years. After 8 years age of son= ( X + 8 ) years. After 8 years age of mother = ( X + 25 + 8 ) = ( X + 33 ) years. According to the question, X+ 8 / X + 33 = 4/9 9 ( X + 8 ) = 4 ( X + 33 ) 9X + 72 = 4X + 132 9X - 4X = 132 - 72 5X = 60 X = 60/5 X = 12 years. Present age of son = X = 12 Years. And, Present age of mother = X + 25 = 12 + 25 = 37 years. ok

Motber is 25 year older than her son. Find son's age if after 8 years ratio of son'sage to mother's age will be4

Answer»

Let present age of son be X years.

Age of mother = ( X + 25 ) years.

After 8 years age of son= ( X + 8 ) years.

After 8 years age of mother = ( X + 25 + 8 ) = ( X + 33 ) years.

According to the question,

X+ 8 / X + 33 = 4/9

9 ( X + 8 ) = 4 ( X + 33 )

9X + 72 = 4X + 132

9X - 4X = 132 - 72

5X = 60

X = 60/5

X = 12 years.

Present age of son = X = 12 Years.

And,

Present age of mother = X + 25 = 12 + 25 = 37 years.