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Motarboat takes 6 hrs. to cover 100km downstream and 30km uostream . if the motorboat goes 75km downstream and returnbacks to it's starting point in 8 hours , find the speed of the motorboat in still water and the rate of stream . |
Answer» solutionLet the speed of the motor boat in STILL water be x km/h.Let the rate of flow of the stream be y km/hSpeed of boat upstream = (x - y) km/h.Speed of boat downstream = (x + y)km/h.we know time = distance/speed.now , A to Q,Time for 100 km downstream and 30 km upstream100/(x + y) + 30/(x - y)And it takes 6 hrs to cover downstream and upstream. Then100/(x + y) + 30/(x - y) = 6Time for 75 km downstream and RETURNING (means 75 km upstream)= 75/(x + y) + 75/(x - y)Given that the time taken is 8 hours75/(x + y) + 75/(x - y) = 8now the equation should be .100P + 30q = 650p + 15q = 3------------( 1 )75p + 75q = 8----------( 2 )from--------( 1 ) &---------( 2 )multiply by ( 3 ) in -----( 1 )250p + 75q = 1575p + 75q = 8(–)______(–)____(–)-------------------------------175p = 7p = 1/25 [ put in -------( 1 ) ]50(1/25) + 15q = 32 + 15q = 3q = 1/15 = 1/(x - y)x - y = 15------------( 3 )p = 1/25 = 1/(x + y)x + y = 25---------( 4 )From---------( 3 ) &----------( 4 )x - y = 15x + y = 25---------------2x = 40x = 20 [ put in ------( 3 ) ]x - y = 1520 - y = 15y = 20 - 15y = 5 , x = 20Hence, the speed of the motor boat in still water is 20 km/h and rate of flow of the stream is 5 km/h.pls follow tannuranna 59 in my following and me ✌️ |
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