1.

Most people interpret a 9.0 dB increase in sound intensity level as a doubling in loudness. By what factor must the sound intensity be increase to double the loudness?

Answer»

`1 m//s`
`2 m//s`
`3 m//s`
`4 m//s`

Solution :`f_(B) = f_(1) - f_(2)`
or `10 = 1700 ((340)/(340 + nu_(2))) - 1700 ((340)/(340 + nu_(1)))`
`= 1700(1 + (nu_(2))/(340))^(-1) - 1700 (1 + (nu_(1))/(340))^(-1)`
USING Binomial therefore, we get
`10 = 1700(1 - (nu_(2))/(340)) - 1700 (1 - (nu_(1))/(340))`
`= (nu_(1) - nu_(2)) ((1700)/(340))`
:. `nu_(1) - nu_(2) = 2 m//s`


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