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Momentum of a particle is increased by `50%`. By how much percentage kinetic energy of particle will increase?

Answer» When momentum is increased by `50%` velocity increases by `50%`, i.e., velcoity becomes `3//2` times, K.E. Becomes `9//4` times, i.e., `(9)/(4)xx100=225%`. Hence, increase in K.E. `=225-100=125%`


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