Saved Bookmarks
| 1. |
Moment of inertia of a thin uniform ring about an axis passing through the center of gravity and perpendicular to the plane is – (a) MR2 (b) 2 MR2 (c) \(\frac{1}{2}\) MR2(d) \(\frac{3}{2}\)MR2 |
|
Answer» Correct answer is (a) MR2 |
|