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Moment of inertia of a cube about an axis passing through the center of mass and perpendicular to face is –(a) \(\frac{Ma^2}{6}\)(b) \(\frac{1}{3}\)Ma2(c) \(\frac{Ma}{6}\)(d) \(\frac{Ma^2}{12}\) |
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Answer» Correct answer is (a) \(\frac{Ma^2}{6}\) |
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