Moment of a force of magnitude 20 N acting along positive x-direction at point (3m,0,0) about the point (0,2,0) (in N-m) is

Moment of a force of magnitude 20 N acting along positive x-direction

1.	Moment of a force of magnitude 20 N acting along positive x-direction at point (3m,0,0) about the point (0,2,0) (in N-m) is
Answer» 20 60 40 30 Solution :TORQUE, `tau=rxxF` `=[(0-3)hat(i)+(2-0)hat(j)+(0-0)hat(k)]XX[20 hat(i)]` `=[3 hat(i)+2hat(j)]xx[20 hat(i)]=-40 hat(k)`.