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Mole fraction of ethanol in aq. solution is 0.4,molality of solution is |
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Answer» Answer: 37.03 m Explanation: Mole FRACTION of ethanol in aq. solution= 0.4 (given) n₁= moles of ethanol n₂= moles of water 0.4= n₁/n₁+n₂ 4/10= n₁/n₁+n₂ n₁=4 and n₂= 10-4= 6 Molality (m)= moles of solute/1 kg of solvent Solvent= 6 moles*18 gm/mol = 108 GMS = 0.108 kg m= 4/.108 = 37.03 m |
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