Home
About Us
Contact Us
Bookmark
Saved Bookmarks
Current Affairs
General Knowledge
Chemical Engineering
UPSEE
BSNL
ISRO
BITSAT
Amazon
ORACLE
Verbal Ability
→
General Awareness
→
IIT JEE in General Awareness
→
Molarity is expressed asA. Gram/litreB. Moles/litr...
1.
Molarity is expressed asA. Gram/litreB. Moles/litreC. Litre/moleD. Moles/1000 gms
Answer» Correct Answer - B
Show Answer
Discussion
No Comment Found
Post Comment
Related InterviewSolutions
`K_(f)` for water is `1.86 K kg mol^(-1)`. IF your automobile radiator holds `1.0 kg` of water, how many grams of ethylene glycol `(C_(2)H_(6)O_(2))` must you add to get the freezing point of the solution lowered to `-2.8^(@)C` ?A. 27 gB. 72 gC. 93 gD. 39 g
For a dilute solution containing `2.5 g` of a non-volatile non-electrolyte solution in `100g` of water, the elevation in boiling point at `1` atm pressure is `2^(@)C`. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of `Hg)` of the solution is: (take `k_(b) = 0.76 K kg mol^(-1))`A. 724B. 740C. 736D. 718
29.2% (W/W) HCI stock solution has a density of 1.25 g `mL^(-1)`. The molecular mass of HCI is 36.5 g `mol^(-1)` Calculate the volume (mL) of stock solution required to prepare 200 mL of 0.4 M HCIA. 2 mLB. 4 mLC. 8 mLD. 6 mL
The freezing point among the following equimolal aqueous solutions will be highest forA. `C_(6)H_(5)NH_(3)Cl` (aniline hydrochloride)B. `Ca(NO_(3))_(2)`C. `La(NO_(3))_(3)`D. `C_(6)H_(12)O_(6)` (glucose)
The amount of urea to be dissolved in 500 ml of water (K = 18.6 K `"mole"^(-1)` in 100 g solvent) to produce a depression of `0.186^(@)C` in freezing point isA. 9 gB. 6 gC. 3 gD. 0.3 g
The normality of `0.3 M` phosphorous acid `(H_(3) PO_(3))` isA. `0.1`B. `0.9`C. `0.3`D. `0.6`
Benzoic acid dissolved in benzene showsA. its normal molecular massB. Double of its normal molecular massC. Half of its normal molecular massD. Not definite.
When benzoic acid dissolve in benzene, the observed molecular mass isA. 244B. 61C. 366D. 122
Four solutions of `K_(2)So_(4)` with the concentrations 0.1m ,0.001 m, and 0.0001 mare available . The maximum value of colligative property corresponds to :A. 0.0001 m solutionB. 0.001 m solutionC. 0.01 m solutionD. 0.1 m solution
Dry air was passed successively through a solution of 5 gm of a solute in 80 gm of water and then through pure ware. The loss in weight of solution was 2.50 gm and that of pure solvent 0.04 gm. What is the molecular weight of the soluteA. `70.31`B. `7.143`C. `714.3`D. 80
Reply to Comment
×
Name
*
Email
*
Comment
*
Submit Reply
Your experience on this site will be improved by allowing cookies. Read
Cookie Policy
Reject
Allow cookies