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Molality of aqu.solution urea having mole fraction 0.2 is |
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Answer» m=mol of solute/ mol of SOLVENT (kg)Mol of solute/mol of solution =mole fraction=0.2 (given)Mol of solution /mol of solute =1/0.2Sub both SIDE by 1Mol ofsolvent/molof SOL=(1/0.2)-1=4Explanation:thus mol of solute/mol of solvent=molality=1/4Pls MARK ad BRAINIEST |
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