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`MnO_(2)` when fused with KOH and oxidized in air gives a dark green compound X. In acidic solution, X undergoes disproportionation to give an intense purple compound Y and `MnO_(2)`. compounds X and Y, respectively, areA. `K_(2)MnO_(4) and KMnO_(4)`B. `Mn_(2)O_(7) and KMnO_(4)`C. `K_(2)MnO_(4) and Mn_(2)O_(7)`D. `KMnO_(4) and K_(2)MnO_(4)` |
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Answer» Correct Answer - A `{:(MnO_(2)+KO_(2)overset("Oxidized")underset("In Air")(to)dark green compound (X)+MnO_(4)^(-2) & K_(2)MnO+_(4)),(" ""Disproportionation"darr),(" ""Purple colour"(Y)+Mnoverset(+4)(O_(2))),(" "overset(" "+7)(KMn)O_(4)):}` `" "(X)toK_(2)MnO_(4)` `" "(Y)toKMnO_(4)` |
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