Saved Bookmarks
| 1. |
Minimum number of capacitors each of `8 muF` and 250 V used to make a composite capacitor of `16 muF` and 1000 V areA. 8B. 32C. 16D. 24 |
|
Answer» Correct Answer - B Minimun number of capacitors in each row ` =(1000)/(250)= 4` Therefore , 4 capacitors connected in series. If there are m such rows, that total cacpacity ` = m xx 2 = 16 " "therefore m = 16//2 8` `therefore` minimum number of capcitors ` = 4 xx 8 = 32` |
|