Minimum number of capacitors each of 4 minutes farad capacitance requi

1.	Minimum number of capacitors each of 4 minutes farad capacitance required to obtain a capacitance of 10 milli farad
Answer» Answer: Explanation: ans : 4 if two capacitors will be in SERIES and two capacitors will be in parallel as shown in figure then, EQUIVALENT CAPACITANCE will 5 microfarad. Let see AB and BC capacitors are in series so, equivalent capacitance {X} of it = 2microfarad/2 = 1 microfarad { in series 1/CEQ = 1/C1 + 1/C2} DE and GF capacitors are in parallel , so, equivalent capacitance { Y} of it = 2 + 2 = 4 microfarad { in parallel, Ceq = C1 + C2 } now, X and Y capacitors are in parallel then, Ceq = 4 + 1 = 5 microfarad.

Minimum number of capacitors each of 4 minutes farad capacitance required to obtain a capacitance of 10 milli farad

Answer»

Answer:

Explanation:

ans : 4

if two capacitors will be in SERIES and two capacitors will be in parallel as shown in figure then, EQUIVALENT CAPACITANCE will 5 microfarad.

Let see AB and BC capacitors are in series

so, equivalent capacitance {X} of it = 2microfarad/2 = 1 microfarad { in series 1/CEQ = 1/C1 + 1/C2}

DE and GF capacitors are in parallel ,

so, equivalent capacitance { Y} of it = 2 + 2 = 4 microfarad { in parallel, Ceq = C1 + C2 }

now, X and Y capacitors are in parallel then,

Ceq = 4 + 1 = 5 microfarad.

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