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☆✿皿 Establish “g = GM//R²” 皿✿☆ |
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Answer» ve:G = GM / R²Solution:Suppose mass of an object placed on the surface of celestial BODY = m mass of celestial body = Mit's radius (Distance between object and centre of celestial body) = R and, universal gravitational CONSTANT = G then, ➡ Weight of the body = Gravitational force exerted by celestial body on the object [So, Using Newton's second law and Newton's universal law of gravitation]➡ mg = GMm/R²➡ mg/m = GM / R²➡ g = GM / R²That is the expression for acceleration due to gravity on any planet or celestial body with mass M and radius R. |
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