Mg(s)|Mg2+(0.1)||Ag+(1×10−3)|AgE∘Ag+/Ag=+0.8volt,E∘Mg2+/Mg=−2 – InterviewSolution

1.	Mg(s)\|Mg2+(0.1)\|\|Ag+(1×10−3)\|AgE∘Ag+/Ag=+0.8volt,E∘Mg2+/Mg=−2.37 voltCalculate the emf of the cell (Round up the answer to two decimal places)(RTF=0.0591 V)
Answer» $M g (s) \| M g^{2 +} (0.1) \| \| A g^{+} (1 \times 10^{- 3}) \| A g$ $E_{A g^{+} / A g}^{\circ} = + 0.8 volt, E_{M g^{2 +} / M g}^{\circ} = - 2.37 volt$ Calculate the emf of the cell (Round up the answer to two decimal places) ( $\frac{R T}{F} = 0.0591 V$ )

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