Mg can reduce NO−3 to NH3 in basic medium. NO−3(aq)+Mg(s)+H2O→Mg(OH)2(s)+OH−(aq)+NH3(g)A 25.0 mL sample of NO−3 solution was treated with Mg(s). The NH3(g) was passed into 100 mL of 0.15 N HCl. The excess of HCl required 32.10 mL of 0.10 N NaOH for neutralization. What was the molarity of NO−3 ions in the original sample?

Mg can reduce NO−3 to NH3 in basic medium. NO−3(aq)+Mg(s)+H2O�

1.	Mg can reduce NO−3 to NH3 in basic medium. NO−3(aq)+Mg(s)+H2O→Mg(OH)2(s)+OH−(aq)+NH3(g)A 25.0 mL sample of NO−3 solution was treated with Mg(s). The NH3(g) was passed into 100 mL of 0.15 N HCl. The excess of HCl required 32.10 mL of 0.10 N NaOH for neutralization. What was the molarity of NO−3 ions in the original sample?
Answer» $M g$ can reduce $N O_{3}^{-}$ to $N H_{3}$ in basic medium. $N O_{3}^{-} (a q) + M g (s) + H_{2} O \to M g (O H)_{2} (s) + O H^{-} (a q) + N H_{3} (g)$ A $25.0 m L$ sample of $N O_{3}^{-}$ solution was treated with $M g (s)$ . The $N H_{3} (g)$ was passed into $100 m L$ of $0.15 N H C l$ . The excess of $H C l$ required $32.10 m L$ of $0.10 N N a O H$ for neutralization. What was the molarity of $N O_{3}^{-}$ ions in the original sample?