(Mensuration)समतलिय चित्र (Plane Surface)1. ए�

1.	(Mensuration)समतलिय चित्र (Plane Surface)1. एउटा त्रिभुजाकार आँगनको किनाराहरू 6 : 5:5 को अनुपातमा छन् रपरिमिति 64 फिट छ । सो आँगनमा प्रति वर्ग फिट रु. 50 को दरलेटाइल बिछ्याउदा कति खर्च लाग्ला ?The edges of a triangular yard is in the ratio of 6 : 5 : 5 andperimeter is 64 feet. What is the total cost of tiling the yard atthe rate of Rs. 50 per square feet.
Answer» Step-by-step explanation: so let edges be 6x ,5x,5x now perimeter is = 64 feet = 6x+5x+5x = 64 = 16x = 64 x= 4 so 6x= 24 ,5x= 20, 5x= 20 now AREA can be FOUND by heron's formula which SAYS s = perimeter/2 = 64/2 = 32 feet and area _/[ 32×(32-24)×(32-20)×(32-20)] _/[32×8×12×12] 12_/(256) 12×16 = 192 per square feet rate of tilling 192×50 = 9600 rs answer

(Mensuration)समतलिय चित्र (Plane Surface)1. एउटा त्रिभुजाकार आँगनको किनाराहरू 6 : 5:5 को अनुपातमा छन् रपरिमिति 64 फिट छ । सो आँगनमा प्रति वर्ग फिट रु. 50 को दरलेटाइल बिछ्याउदा कति खर्च लाग्ला ?The edges of a triangular yard is in the ratio of 6 : 5 : 5 andperimeter is 64 feet. What is the total cost of tiling the yard atthe rate of Rs. 50 per square feet.

Answer»

Step-by-step explanation:

so let edges be

6x ,5x,5x

now perimeter is = 64 feet

= 6x+5x+5x = 64

= 16x = 64

x= 4

6x= 24 ,5x= 20, 5x= 20

now AREA can be FOUND by heron's formula

which SAYS

s = perimeter/2 = 64/2 = 32 feet

and area

_/[ 32×(32-24)×(32-20)×(32-20)]

_/[32×8×12×12]

12_/(256)

12×16 = 192 per square feet

rate of tilling

192×50 = 9600 rs answer