Meena is three times as old as Leena . after 5 years , she will be as

1.	Meena is three times as old as Leena . after 5 years , she will be as twice as age of Leena , find there present ages
Answer» Answer :- Let present age of meena = X years Let present age of meena's MOTHER =Y years After five years age of meena =(x + 5) years After five years age of meen's mother =(Y +5) years According to question $y = 4x - - - (1)$ $y + 5 = 3(x + 5) - - - (<klux>2</klux>)$ Put (1) in (2) , we get $4x + 5 = 3x + 15$ $4x - 3x = 15 - 5$ $x = 10$ $y = <klux>40</klux>$ Meena's present age =10 years Meena's mother's present age =40 years