1.

Measure of two quantities along with the precision of respective measuring instrument is `A=2.5ms^(-1)+-0.5ms^(-1)`,B=0.10s+-0.01s`. The value of AB will beA. `(0.25+-0.08)m`B. `(0.25+-0.5)`mC. `(0.25+-0.05)`mD. `(0.25+-0.135)`m

Answer» Correct Answer - A
`A=2.5ms^-1+-0.5ms^-1`,`B=0.10s+-0.01s`
`x=AB=(2.5)(0.10)=0.25m`
`(trianglex)/(x)=(triangleA)/(A)+(triangleB)/(B)`
`(0.5)/(2.5)+(0.1)/(0.10)=(0.05+0.025)/(0.25)=(0.075)/(0.25)`
`trianglex=0.075=0.08m`
Rounding off to two significant figures.
`AB=(0.25+-0.08)m`


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