Me−C≡C−MeNa/NH3(liq.)−−−−−−−−→EtOH,−33∘CX= – InterviewSolution

1.	Me−C≡C−MeNa/NH3(liq.)−−−−−−−−→EtOH,−33∘CX=dil.alkaline KMnO4−−−−−−−−−−−−→ Product(s) The product(s) from the above reaction will be
Answer» $M e - C \equiv C - M e N a / N H_{3} (l i q .) - ------- \to E t O H, - 33^{\circ} C X = d i l . a l k a l i n e K M n O_{4} - ----------- \to$ Product(s) The product(s) from the above reaction will be

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