1.

Maximum uncertainty in position of a proton is6xx10^(-8)m .Uncertainty in measurement of its velocity will be …….(h=6.625xx10^(-34))Js,Mass of proton =1.67xx10^(-27) kg

Answer»

`1mms^(-1)`
`1MS^(-1)`
`1cms^(-1)`
`100 MS^(-1)`

Solution :From Heisenberg.s principle of uncertainty,
Uncertainty in momentum `Deltap=(h)/(2piDeltax)`
`THEREFORE Deltap=(6.625xx10^(-34))/(2xx3.14xx6xx10^(-8))`
`therefore Deltap=0.1758xx10^(-26)`
`therefore mDeltav=0.1758xx10^(-26)`
`therefore Deltap=(0.1758xx10^(-26))/(m)`
`=(0,1758xx10^(-26))/(1.67xx10^(-27))=0.105269xx10^(1)`
Uncertainty in velocity `therefore Deltav~~1.0 ms^(-1)`


Discussion

No Comment Found

Related InterviewSolutions