Maximisation of Revenue.

1.	Maximisation of Revenue.
Answer» x Demand of an item, p = Price per unit of an item, Revenue R = x . p. The conditions for maximisation of revenue are as follows: Necessary condition: \(\frac{dR}{dx}\) = 0 Sufficient condition: \(\frac{d^2R}{dx^2}\) < 0 (Negative)

Answer»

x Demand of an item, p = Price per unit of an item, Revenue R = x . p.
The conditions for maximisation of revenue are as follows:

Discussion

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If `f(theta) = sin(tan^(-1)(sintheta/sqrt(cos2theta)))`, where `-pi/4 lt theta lt pi/4,` then the value of `d/(d(tantheta)) f(theta)` is