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Maths question don't spam​

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ANSWER :

The center is (1,-3) and the radius is r=5 UNITS.

EXPLANATION :

The GIVEN equation is:

{x}^{2} + {y}^{2} - 2x + 6y - 15 = 0

Let rearrange to GET:

{x}^{2} - 2x + {y}^{2} + 6y=15

We complete the square to get;

{x}^{2} - 2x + ( { - 1)}^{2} + {y}^{2} + 6y + {3}^{2} = 15+ ( { - 1)}^{2} + {3}^{2}

( {x - 1)}^{2} +( {y + 3)}^{2} = 15 + 1+ 9

( {x - 1)}^{2} +( {y + 3)}^{2} =25

( {x - 1)}^{2} +( {y + 3)}^{2} = {5}^{2}

COMPARING to

( {x - h)}^{2} +( {y - h)}^{2} = {r}^{2}

The center is (1,-3) and the radius is r=5 units.


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