Mathematics - Perimeter and AreaThe length and breadth of a rectangula

1.	Mathematics - Perimeter and AreaThe length and breadth of a rectangular piece of land are, in the ratio 5:2. If the total cost of fencing it at Rs. 12.5per meter is Rs. 25000, find its length and breadth.
Answer» Answer: Length = 714.25 metres, Breadth = 285.7 metres. (approximately) Step by step explanation: Given: Ratio of length and breadth of rectangular PIECE of land = 5 : 2. Cost of fencing per m: Rs. 12.5 per m. Total cost: Rs. 25,000. To find: Length and breadth. SOLUTION: Total cost of fencing / Rate per m = Perimeter .°. 25000/12.5 = Perimeter Perimeter = 2000 metres Now, let the length be 5X and breadth be 2X. Perimeter of rectangular piece of land= 2( length + breadth) 2000 = 2 ( 5x + 2x ) 2000 = 2 × 7x 1000 = 7x X = 142.85 metres. (approx.) Length = 5x = 5 × 142.85 = 714.25 metres (approx.) Breadth = 2x = 2 × 142.85 = 285.70 metres (approx.) Thus, It's length and breadth are 714.25 metres and 285.7 metres (approx.) respectively.

Mathematics - Perimeter and AreaThe length and breadth of a rectangular piece of land are, in the ratio 5:2. If the total cost of fencing it at Rs. 12.5per meter is Rs. 25000, find its length and breadth.

Answer»

Answer: Length = 714.25 metres, Breadth = 285.7 metres. (approximately)

Step by step explanation:

Given:

Ratio of length and breadth of rectangular PIECE of land = 5 : 2.

Cost of fencing per m: Rs. 12.5 per m.

Total cost: Rs. 25,000.

To find: Length and breadth.

Total cost of fencing / Rate per m = Perimeter

.°. 25000/12.5 = Perimeter

Perimeter = 2000 metres

Now, let the length be 5X and breadth be 2X.

Perimeter of rectangular piece of land= 2( length + breadth)

2000 = 2 ( 5x + 2x )

2000 = 2 × 7x

1000 = 7x

X = 142.85 metres. (approx.)

Length = 5x = 5 × 142.85 = 714.25 metres (approx.)

Breadth = 2x = 2 × 142.85 = 285.70 metres (approx.)

Thus, It's length and breadth are 714.25 metres and 285.7 metres (approx.) respectively.