MATHEMATICPA(vi Thètaxi charges in a city cónsšist of a fixed charg

1.	MATHEMATICPA(vi Thètaxi charges in a city cónsšist of a fixed chargo-togetheravith ihs 1o5 and for a ofthe charge for thedistance covered. Fori a distance of 10 km, the charge paidlajourney of 15 km, the charge paid is Rs 155. What areeharge per km? How much does a person have to pay for tr velling a25 km?togetherwith0or andthe denominator
Answer» Letthe fixed chargefor taxi= Rs x Andvariable cost per Km= Rs y Total cost= fixed charge + variable charge Given that for a distance of 10 km, the charge paid is Rs 105 x + 10 y= 105… (1) x= 105 – 10 y Given that for a journey of 15 km, the charge paid is Rs 155 x + 15 y= 155 Plug the value of x we get 105 – 10 y + 15 y= 155 5y= 155 – 105 5y= 50 Divide by 5we get y= 50 / 5= 10 Plug this value in equation (1) we get x= 105 – 10 * 10 x= 5 People have to pay for traveling a distance of 25 km = x + 25 y = 5 + 25*10 = 5 + 250 =255 Answer pay for 25 Km is Rs 255

MATHEMATICPA(vi Thètaxi charges in a city cónsšist of a fixed chargo-togetheravith ihs 1o5 and for a ofthe charge for thedistance covered. Fori a distance of 10 km, the charge paidlajourney of 15 km, the charge paid is Rs 155. What areeharge per km? How much does a person have to pay for tr velling a25 km?togetherwith0or andthe denominator

Answer»

Letthe fixed chargefor taxi= Rs x

Andvariable cost per Km= Rs y

Total cost= fixed charge + variable charge

Given that for a distance of 10 km, the charge paid is Rs 105

x + 10 y= 105… (1)

x= 105 – 10 y

Given that for a journey of 15 km, the charge paid is Rs 155

x + 15 y= 155

Plug the value of x we get

105 – 10 y + 15 y= 155

5y= 155 – 105

5y= 50

Divide by 5we get

y= 50 / 5= 10

Plug this value in equation (1) we get

x= 105 – 10 * 10

x= 5

People have to pay for traveling a distance of 25 km

= x + 25 y

= 5 + 25*10

= 5 + 250

=255

Answer pay for 25 Km is Rs 255