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Match standard free energy of the reaction with the corresponding equilibrium constant `{:((i) ,DeltaG^(Θ)gt0,,(a),K gt 1),((ii),DeltaG^(Θ) lt 0,,(b) ,K=1),((iii),DeltaG^(Θ) = 0 ,,(c),K=0),(,,,(d),K lt 1),(,,,,):}` |
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Answer» Correct Answer - (i)-(d), (ii)-(a), (iii)-(b) `DeltaG^(@)` = - RT ln K (i) If `DeltaG^(@) gt 0`, i.e., `Delta^(@)` is +ve, then ln K is -ve, i.e., `K lt 1` . Hence, (i)-(d). (ii) If `DeltaG^(@) lt 0`, i.e., `DeltaG^(@)` is -ve, then ln K is +ve, i.e., `K gt 1`. Hence, (ii) -(a). (iii) If `DeltaG^(@)= 0`, ln K = 1 , i.e., K = 1. Hence, (iii)-(b). |
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