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Mass of ""_(3)^(7) Li is 7.016004 amu. Mass of proton is 1.007277 amu and mass of neutron is 1.008665 amu. Mass defect of lithium nucleus in amu is

Answer»

`0.04948` amu
`0.04050` amu
`0.04052` amu
`0.04055` amu

Solution :No. of PROTONS in `""_(3)^(7)LI = 3`
and NEUTRONS = `7- 3 = 4`.
Mass of 3p and 4n = `3 XX 1.007277 + 4 xx 1.008665` amu
`= 7.056491` amu
`:.` Mass defect = `7.056491 - 7.016005 = 0.040486` amu.


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