1.

Maria invested rupees 8000 in a business . she would be paid interest at 5% per annum compounded annually .find(i) The amount credited against her name at the end of second year .(ii) The interest for the third year. ​

Answer»

\huge \sf\underline\red{Question}

Maria invested rupees 8000 in a business . she would be paid interest at 5% per annum COMPOUNDED annually .

Find -:

(i) The amount credited against her name at the end of second year .

(ii) The interest for the third year.

\huge \sf\underline\red{Solution}

\bf \blue{Here \: we \: have,}

\fbox \pink{P = Rs.8000}

\fbox\pink{R = Rs. 5 \: percent \: p.a}

\fbox \pink{n = 2 \: years}

\bf \blue{(i) \: Amount \: after \: 2 \: years}

\fbox \purple{A2 \: =P(1 + \frac{R }{100} )n }

\fbox \purple{ \: =8000(1 + \frac{5 }{100} ) {}^{2} } = \fbox \purple{ = 8000( 1 + \frac{1}{20} ) {}^{2} }

\fbox \purple{ = 8000 \times \frac{21}{20} \times \frac{21}{20} } = \fbox \pink{Rs. \: 8820}

\bf \blue {A2 = Rs. \: 8820}

\sf\green{→Amount \: after \: 2 \: years \: = Rs. 8,820}

\bf \blue{(ii)Now \: amount \: after \: 3 \: years}

\fbox \purple{A3 \: =P(1 + \frac{R }{100} )n }

A3=\fbox \purple{ \: =8000(1 + \frac{5 }{100} ) {}^{3} } = \fbox \purple{ = 8000( 1 + \frac{1}{20} ) {}^{3} }

\fbox \purple{ = 8000 ( \frac{21}{20} ) {}^{3} }

\fbox \purple{ \frac{8000 \times 21 \times 21 \times 21}{20 \times 20 \times 20} } \: \fbox \pink{Rs. \: 9261}

\bf \blue {→Interest \: for \: 3rd \: year \: = A3 -A2}

\fbox \orange{Rs.(9261 - 8820)} = \fbox \red{Rs.441.}

\sf \green{→So, \: interest \: for \: 3rd \: year \: = Rs.441}

I am having another version of brainly so my answer is in that way as you SEE in above attachments⬆️

\sf\underline\red{Hope \: It \: Helps \: You}


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