1.

Maria deposited Rs 80,000 in a bank for 2 years at the rate 5% per annumcompounded annually. Find the compound interest after 2 years?​

Answer»

Answer:

\bold\green{Compound\:<klux>INTEREST</klux> } = \bold{Rs.8,200}

Step-by-step EXPLANATION:

\bf\red{Given}\begin{cases}\sf\green{Principal(P) = Rs.80,000}\\\sf\orange{Time(n) = 2\:years}\\\sf\purple{Rate\:of\:interest(r) = 5\%}\\\sf\red{Compound\:interst(CI) = ?}\end{cases}

We know formula of Compound interest:-

{\boxed{\bold\red{CI = P{(1+r)}^{n} - P}}}

\hookrightarrow\sf CI = 80,000{(1+5\%)}^{2} - 80,000 \\\\\hookrightarrow\sf CI = 80,000 {(1+\dfrac{5}{100} )}^{2} - 80,000 \\\\\hookrightarrow\sf CI = 80,000 {(\dfrac{100+5}{100})}^{2} - 80,000 \\\\\hookrightarrow\sf CI = 80,000 {(\dfrac{105}{100})}^{2} - 80,000 \\\\\hookrightarrow\sf CI =  80,000 \times {(1.05)}^{2} - 80,000 \\\\\hookrightarrow\sf CI = 80,000 \times 1.1025 - 80,000 \\\\\hookrightarrow\sf CI = 88,200 - 80,000 \\\\\hookrightarrow\huge{\boxed{\sf\green{CI = Rs.8,200 }}}

\therefore\bold{\underline{Compound\:interest = Rs.8,200}}



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