Make 3 different 3 digit numbers using 2, 3, 4 where each digit can be

1.	Make 3 different 3 digit numbers using 2, 3, 4 where each digit can be used only once, Check which of these numbers is divisible by 9.
Answer» 3 different 3-digit numbers using 2, 3, 4 are 234, 342, 243 Given digits 2, 3 & 4; their sum = 2 + 3 + 4 = 9, Any number formed by these digits is always divisible by 9. a) Sum of the digits of 234 = 2 + 3 + 4 = 9 is divisible by 9. If the sum of the digits of the number is divisible by 9. So, 234 is divisible by 9. b) Sum of the digits of 342 = 3 + 4 + 2 = 9 is divisible by 9. So, 342 is divisible by 9. c) Sum of the digits of 243 = 2 + 4 + 3 = 9 is divisible by 9. So, 243 is divisible by 9.

Make 3 different 3 digit numbers using 2, 3, 4 where each digit can be used only once, Check which of these numbers is divisible by 9.

Answer»

3 different 3-digit numbers using 2, 3, 4 are 234, 342, 243

Given digits 2, 3 & 4; their sum = 2 + 3 + 4 = 9,

Any number formed by these digits is always divisible by 9.

a) Sum of the digits of 234

= 2 + 3 + 4 = 9 is divisible by 9.

If the sum of the digits of the number is divisible by 9.

So, 234 is divisible by 9.

b) Sum of the digits of 342 = 3 + 4 + 2 =

9 is divisible by 9.

So, 342 is divisible by 9.

c) Sum of the digits of 243 = 2 + 4 + 3 =

9 is divisible by 9.

So, 243 is divisible by 9.