1.

Magnitude of wave vector of an e.m.wave with frequency 150 MHz is ...... rad/s.

Answer»

`PI`
`pi/2`
`(3pi)/(2)`
`(3pi)/(4)`

SOLUTION :We know, `v= (omega)/(k)`
`therefore k = (omega)/(v) = (2pi f )/ (c ) (because` for e.m. wave we have v =c)
`therefore k = (2 xx pi xx 150 xx 10^(6))/( 3xx 10 ^(8))`
`therefore k = pi rad //m`


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